具有半导体导电特性的腈纶研究

研究了由二价铜盐、还原剂和硫化剂浴液处理法制备导电性腈纶的影响因素、实施方法、导电性腈纶的结构和性能，确定了适宜的工艺条件。研究表明：一浴法和二浴法处理的反应历程和处理结果基本相同，但还原剂、硫化剂的匹配及用量不同；导电化处理后腈给大分子排列的规整性略有下降，宏观形态及物理机械性能无明显变化；当纤维中Ｃｕ９Ｓ５含量达１２．５％时，质量比电阻下降至１０－１Ω·ｇ／ｃｍ２以下。纤维具有明显的半导体导电特性。     

在带有奇异性的黎曼流形中具有零曲率,负曲率和指定曲率的全共形尺度

本文考察在什么时候一个非紧黎曼流形Ｍ上存在着一个全共形尺度，该尺度随具有零、负和指定曲率的已知的闭子流形而增大，其中，Ｍ是由从一个紧黎曼流形Ｍ＾Ｎ（Ｎ≥３）中除去ｍ（ｍ≥２）个闭子流形Г＾ｎｉｉ（１≤ｉ≤ｍ）而得到，特别，本文证明了上述考察是肯定的：（１）对负曲率情形，其充分条件是ｎｉ＞（Ｎ－２）／２（１≤ｉ≤ｍ）；（２）对零曲率的情形，其条件是ｎｉ≤（Ｎ－２）／２，以及索勃列夫商为正；（３）对在     

运输需求的特性及其分析特点

研究了运输需求的概念和特性，粗略地总结了运输需求的广泛性、多样性、派生性、空间特定性、时间特定性和部分可替代性６个主要特征，说明运输需求包括流量、流向、流程、流时和流速５个要素。并分析了运输需求的产生原因，讨论了运输需求分析的特点，论述了微观经济学需求理论用于运输需求分析的局限性。     

职校学习后进生的形成原因与教育对策

在职业学校里客观上存在着极少数学习困难、成绩落后的学生，这些学生是教师日常教育教学的重点和难点。本文对学习后进生的形成原因进行比较全面的调查研究，在此基础上采取相应有效的教育对策是成功转化学习后进生的关键。     

HEp-2细胞MPM-2磷蛋白的蛋白质组学分析

MPM-2磷蛋白家族成员在有丝分裂进程中起着重要作用．为了从MPM-2磷蛋白家族层面入手研究细胞周期调控中磷蛋白的重要作用，以人上皮样喉癌细胞株HEp-2为细胞模型，运用双向电泳、免疫印迹以及质谱技术等蛋白质组学的方法对其细胞抽提物中的部分MPM-2磷蛋白进行了分析鉴定，初步确定了乙二醛酶(GlyoxalaseⅠ)、真核翻译起始因子(eIF4B)以及核质蛋白NPM等MPM-2特异识别的细胞磷蛋白，这将有助于进一步研究MPM2磷蛋白家族成员在细胞周期调控中的重要作用．     

试谈动态思维训练

在物理量相互制约的物理习题中,有一类A量取得特殊值,B量取极值问题。可称“条件极值题”。本文探讨了用《高中物理客观性命题研究》中习题训练动态思维。     

农村移民职业教育培训与万州区实施城市化战略的思考

重庆市万州区城市化战略能否顺利实现,除了受制于人口管理,就业机会、土地制度、政府职能等因素外,很大程度上取决于广大农村移民人口的科学文化素质和文明程度.区政府要从提高移民的自身素质和职业能力出发,加强"三教"统筹,发挥城市教育资源的优势,完善农村移民职业教育培训体系,加大对农村移民劳动力转移培训的扶持力度,通过各种形式的培训,促进农村移民的城市化转变.     

Ruin Probability with Variable Premium Rate and Disturbed by Diffusion in a Markovian Environment

We consider a risk model with a premium rate which varies with the level of free reserves. In this model, the occurrence of claims is described by a Cox process with Markov intensity process, and the influence of stochastic factors is considered by adding a diffusion process. The integro-differential equation for the ruin probability is derived by a infinitesimal method.     

Newton's Easy Quadratures ``Omitted for the Sake of Brevity'

In the 1687 Principia, Newton gave a solution to the direct problem (given the orbit and center of force, find the central force) for a conic-section with a focal center of force (answer: a reciprocal square force) and for a spiral orbit with a polar center of force (answer: a reciprocal cube force). He did not, however, give solutions for the two corresponding inverse problems (given the force and center of force, find the orbit). He gave a cryptic solution to the inverse problem of a reciprocal cube force, but offered no solution for the reciprocal square force. Some take this omission as an indication that Newton could not solve the reciprocal square, for, they ask, why else would he not select this important problem? Others claim that ``it is child's play' for him, as evidenced by his 1671 catalogue of quadratures (tables of integrals). The answer to that question is obscured for all who attempt to work through Newton's published solution of the reciprocal cube force because it is done in the synthetic geometric style of the 1687 Principia rather than in the analytic algebraic style that Newton employed until 1671. In response to a request from David Gregory in 1694, however, Newton produced an analytic version of the body of the proof, but one which still had a geometric conclusion. Newton's charge is to find both ``the orbit' and ``the time in orbit.' In the determination of the dependence of the time on orbital position, t(r), Newton evaluated an integral of the form ∫dx/x <sup>n</sup> to calculate a finite algebraic equation for the area swept out as a function of the radius, but he did not write out the analytic expression for time t = t(r), even though he knew that the time t is proportional to that area. In the determination of the orbit, θ (r), Newton obtained an integral of the form ∫dx/√(1−x<sup>2</sup>) for the area that is proportional to the angle θ, an integral he had shown in his 1669 On Analysis by Infinite Equations to be equal to the arcsin(x). Since the solution must therefore contain a transcendental function, he knew that a finite algebraic solution for θ=θ(r) did not exist for ``the orbit' as it had for ``the time in orbit.' In contrast to these two solutions for the inverse cube force, however, it is not possible in the inverse square solution to generate a finite algebraic expression for either ``the orbit' or ``the time in orbit.' In fact, in Lemma 28, Newton offers a demonstration that the area of an ellipse cannot be given by a finite equation. I claim that the limitation of Lemma 28 forces Newton to reject the inverse square force as an example and to choose instead the reciprocal cube force as his example in Proposition 41. (Received August 14, 2002) Published online March 26, 2003 Communicated by G. Smith     

泡沫的持液量研究

泡沫的持液量（ｈ，ｍｇ／ｃｍ３）是泡沫的基本特性之一．本文对形成泡沫的起泡剂浓度、增粘剂浓度、气体流量和温度等因素对Ｈ的影响及变化规律作了研究，并对Ｈ与泡沫表观粘度和泡沫半衰期的相互关系作了描述，对泡沫的实际应用具有一定的指导意义．